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发表于 2012-9-29 13:25:33
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原帖由 <i>2011wosliming</i> 于 2012-9-29 00:19 发表 <a href="http://bbs.wuyou.net/redirect.php?goto=findpost&pid=2574290&ptid=256981" target="_blank"><img src="http://bbs.wuyou.net/images/common/back.gif" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" onmousewheel="return imgzoom(this);" alt="" /></a><br />
论坛求助,<br />
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现在用笔记本连接两个网段,想获得有线连接的本机ip 以及这个网段的在线的电脑的ip地址<br />
<br />
使用net view ,可是在判断哪一个是有线连接上,不知道如何办,<br />
<br />
朋友提供的代码,<br />
<br />
<br />
@echo off<br />
... <br />
把后面那个FOR 语句丢掉垃圾桶里去
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